t^(1/2)-10t^(1/4)+25=0

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Solution for t^(1/2)-10t^(1/4)+25=0 equation: 


D( t )

t < 0

t < 0

t in <0:+oo)

t^(1/2)-(10*t^(1/4))+25 = 0

t^(1/2)-10*t^(1/4)+25 = 0

t_1 = t^(1/4)

1*t_1^2-10*t_1^1+25 = 0

t_1^2-10*t_1+25 = 0

DELTA = (-10)^2-(1*4*25)

DELTA = 0

t_1 = 10/(1*2)

t_1 = 5 or t_1 = 5

t_1 = 5

t^(1/4)-5 = 0

1*t^(1/4) = 5 // : 1

t^(1/4) = 5

t^(1/4) = 5 // ^ 4

t = 625

t_1 = 5

t^(1/4)-5 = 0

1*t^(1/4) = 5 // : 1

t^(1/4) = 5

t^(1/4) = 5 // ^ 4

t = 625

t in { 625, 625 }

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